What are the solutions to the equation 4(x-3)^2+24x=0 ?

The solutions to the equation 4(x-3)^2+24x=0 are x=3i,x=-3i

Find the zeros of 4(x-3)^2+24x=0

The zeros of 4(x-3)^2+24x=0 are x=3i,x=-3i

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4 (x - 3)^{2} + 24 x = 0

x = 3 i, x = - 3 i

Solution steps

4 (x - 3)^{2} + 24 x = 0

Expand

4 (x - 3)^{2} + 24 x : 4 x^{2} + 36

4 x^{2} + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 \cdot 36}{2 \cdot 4}

Simplify

0^{2} - 4 \cdot 4 \cdot 36 : 24 i

x_{1, 2} = \frac{- 0 \pm 24 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 24 i}{2 \cdot 4}, x_{2} = \frac{- 0 - 24 i}{2 \cdot 4}

x = \frac{- 0 + 24 i}{2 \cdot 4} : 3 i

x = \frac{- 0 - 24 i}{2 \cdot 4} : - 3 i

The solutions to the quadratic equation are:

x = 3 i, x = - 3 i

A (n) = (700 + n) (10 - 0.001 n)

- 5 x^{2} + 350 x - 3000 = 0

3 (x - 9)^{2} = 21

- 2 x^{2} + 9 x - 9 = 0

(X^{1} + X^{2}) = 5

What are the solutions to the equation 4(x-3)^2+24x=0 ?
The solutions to the equation 4(x-3)^2+24x=0 are x=3i,x=-3i
Find the zeros of 4(x-3)^2+24x=0
The zeros of 4(x-3)^2+24x=0 are x=3i,x=-3i