What are the solutions to the equation -2x^2+9x-9=0 ?

The solutions to the equation -2x^2+9x-9=0 are x= 3/2 ,x=3

Find the zeros of -2x^2+9x-9=0

The zeros of -2x^2+9x-9=0 are x= 3/2 ,x=3

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- 2 x^{2} + 9 x - 9 = 0

x = \frac{3}{2}, x = 3

Decimal Notation

x = 1.5, x = 3

Solution steps

- 2 x^{2} + 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

9^{2} - 4 (- 2) (- 9) = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 ( - 2 )}, x_{2} = \frac{- 9 - 3}{2 ( - 2 )}

x = \frac{- 9 + 3}{2 ( - 2 )} : \frac{3}{2}

x = \frac{- 9 - 3}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 3

(X^{1} + X^{2}) = 5

3 x^{2} - 90 x + 243 = 0

x^{2} - 4 x - 2 = 3

x^{2} = 4 x - 14

24 x^{2} - 28 x + 13 = 0

What are the solutions to the equation -2x^2+9x-9=0 ?
The solutions to the equation -2x^2+9x-9=0 are x= 3/2 ,x=3
Find the zeros of -2x^2+9x-9=0
The zeros of -2x^2+9x-9=0 are x= 3/2 ,x=3