What are the solutions to the equation 16x^2-147x+245=0 ?

The solutions to the equation 16x^2-147x+245=0 are x=7,x= 35/16

Find the zeros of 16x^2-147x+245=0

The zeros of 16x^2-147x+245=0 are x=7,x= 35/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} - 147 x + 245 = 0

x = 7, x = \frac{35}{16}

Decimal Notation

x = 7, x = 2.1875

Solution steps

16 x^{2} - 147 x + 245 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 147 ) \pm ( - 147 ) ^{2} - 4 \cdot 16 \cdot 245}{2 \cdot 16}

(- 147)^{2} - 4 \cdot 16 \cdot 245 = 77

x_{1, 2} = \frac{- ( - 147 ) \pm 77}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 147 ) + 77}{2 \cdot 16}, x_{2} = \frac{- ( - 147 ) - 77}{2 \cdot 16}

x = \frac{- ( - 147 ) + 77}{2 \cdot 16} : 7

x = \frac{- ( - 147 ) - 77}{2 \cdot 16} : \frac{35}{16}

The solutions to the quadratic equation are:

x = 7, x = \frac{35}{16}

5 x^{2} + 4 x + 10 = 0

2 x^{2} - 8 = 0

(x - 3)^{2} = 4 (x - 3)

x^{2} + 2 x = e^{3}

s, s^{2} + 2 s - 98 = 0

What are the solutions to the equation 16x^2-147x+245=0 ?
The solutions to the equation 16x^2-147x+245=0 are x=7,x= 35/16
Find the zeros of 16x^2-147x+245=0
The zeros of 16x^2-147x+245=0 are x=7,x= 35/16