What are the solutions to the equation 5x^2+4x+10=0 ?

The solutions to the equation 5x^2+4x+10=0 are x=-2/5+i(sqrt(46))/5 ,x=-2/5-i(sqrt(46))/5

Find the zeros of 5x^2+4x+10=0

The zeros of 5x^2+4x+10=0 are x=-2/5+i(sqrt(46))/5 ,x=-2/5-i(sqrt(46))/5

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5 x^{2} + 4 x + 10 = 0

x = - \frac{2}{5} + i \frac{46}{5}, x = - \frac{2}{5} - i \frac{46}{5}

Solution steps

5 x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 10 : 246 i

x_{1, 2} = \frac{- 4 \pm 2 46 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 46 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 46 i}{2 \cdot 5}

x = \frac{- 4 + 2 46 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{46}{5}

x = \frac{- 4 - 2 46 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{46}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{46}{5}, x = - \frac{2}{5} - i \frac{46}{5}

2 x^{2} - 8 = 0

(x - 3)^{2} = 4 (x - 3)

x^{2} + 2 x = e^{3}

s, s^{2} + 2 s - 98 = 0

0.18 = (1 + \frac{j}{2})^{2} - 1

What are the solutions to the equation 5x^2+4x+10=0 ?
The solutions to the equation 5x^2+4x+10=0 are x=-2/5+i(sqrt(46))/5 ,x=-2/5-i(sqrt(46))/5
Find the zeros of 5x^2+4x+10=0
The zeros of 5x^2+4x+10=0 are x=-2/5+i(sqrt(46))/5 ,x=-2/5-i(sqrt(46))/5