What are the solutions to the equation -3y^2+2y+8=0 ?

The solutions to the equation -3y^2+2y+8=0 are y=-4/3 ,y=2

Find the zeros of -3y^2+2y+8=0

The zeros of -3y^2+2y+8=0 are y=-4/3 ,y=2

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- 3 y^{2} + 2 y + 8 = 0

y = - \frac{4}{3}, y = 2

Decimal Notation

y = - 1.33333 \dots, y = 2

Solution steps

- 3 y^{2} + 2 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 8 = 10

y_{1, 2} = \frac{- 2 \pm 10}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- 2 + 10}{2 ( - 3 )}, y_{2} = \frac{- 2 - 10}{2 ( - 3 )}

y = \frac{- 2 + 10}{2 ( - 3 )} : - \frac{4}{3}

y = \frac{- 2 - 10}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

y = - \frac{4}{3}, y = 2

5232.6 x^{2} - 196250 x - 15072000 = 0

x^{2} + 10 x + 45 = 26

x, x^{2} + 3 x y + y^{3} = 20

5 a^{2} + 4 a = - 2 + 2 a

x, 4 x^{2} - 3 x y - 18 = 0

What are the solutions to the equation -3y^2+2y+8=0 ?
The solutions to the equation -3y^2+2y+8=0 are y=-4/3 ,y=2
Find the zeros of -3y^2+2y+8=0
The zeros of -3y^2+2y+8=0 are y=-4/3 ,y=2