What are the solutions to the equation -2x^2+x-2=0 ?

The solutions to the equation -2x^2+x-2=0 are x= 1/4-i(sqrt(15))/4 ,x= 1/4+i(sqrt(15))/4

Find the zeros of -2x^2+x-2=0

The zeros of -2x^2+x-2=0 are x= 1/4-i(sqrt(15))/4 ,x= 1/4+i(sqrt(15))/4

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- 2 x^{2} + x - 2 = 0

x = \frac{1}{4} - i \frac{15}{4}, x = \frac{1}{4} + i \frac{15}{4}

Solution steps

- 2 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

Simplify

1^{2} - 4 (- 2) (- 2) : 15 i

x_{1, 2} = \frac{- 1 \pm 15 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 15 i}{2 ( - 2 )}, x_{2} = \frac{- 1 - 15 i}{2 ( - 2 )}

x = \frac{- 1 + 15 i}{2 ( - 2 )} : \frac{1}{4} - i \frac{15}{4}

x = \frac{- 1 - 15 i}{2 ( - 2 )} : \frac{1}{4} + i \frac{15}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{15}{4}, x = \frac{1}{4} + i \frac{15}{4}

(x + 7) (2 x - 7) = 0

y^{2} + \frac{18}{5} y + \frac{81}{25} = 0

5 w^{2} + 13 w = - 6

x^{2} + 4 x + 5 = 0

0 + \frac{x ^{2}}{25} = 400

What are the solutions to the equation -2x^2+x-2=0 ?
The solutions to the equation -2x^2+x-2=0 are x= 1/4-i(sqrt(15))/4 ,x= 1/4+i(sqrt(15))/4
Find the zeros of -2x^2+x-2=0
The zeros of -2x^2+x-2=0 are x= 1/4-i(sqrt(15))/4 ,x= 1/4+i(sqrt(15))/4