What are the solutions to the equation (x+a)^2-b^2=0 ?

The solutions to the equation (x+a)^2-b^2=0 are x=b-a,x=-b-a

Find the zeros of (x+a)^2-b^2=0

The zeros of (x+a)^2-b^2=0 are x=b-a,x=-b-a

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(x + a)^{2} - b^{2} = 0

x = b - a, x = - b - a

Solution steps

(x + a)^{2} - b^{2} = 0

Move

b^{2}

to the right side

(x + a)^{2} = b^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + a = b^{2} : x = b - a

Solve

x + a = - b^{2} : x = - b - a

The solutions to the quadratic equation are:

x = b - a, x = - b - a

2 x^{2} - 3 x + 1 = 0

\frac{1}{8} x^{2} - \frac{3}{4} x + 1 = 0

0.0102 s^{2} + 0.5151 s + 1.255 = 0

3 x (x - 2) = 8 x^{2} - 7 x

5 x^{2} + 3 x - 14 = - 11 x + 10

What are the solutions to the equation (x+a)^2-b^2=0 ?
The solutions to the equation (x+a)^2-b^2=0 are x=b-a,x=-b-a
Find the zeros of (x+a)^2-b^2=0
The zeros of (x+a)^2-b^2=0 are x=b-a,x=-b-a