What are the solutions to the equation 300-40x+4x^2=300-20x+4/3 x^2 ?

The solutions to the equation 300-40x+4x^2=300-20x+4/3 x^2 are x= 15/2 ,x=0

Find the zeros of 300-40x+4x^2=300-20x+4/3 x^2

The zeros of 300-40x+4x^2=300-20x+4/3 x^2 are x= 15/2 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

300 - 40 x + 4 x^{2} = 300 - 20 x + \frac{4}{3} x^{2}

x = \frac{15}{2}, x = 0

Decimal Notation

x = 7.5, x = 0

Solution steps

300 - 40 x + 4 x^{2} = 300 - 20 x + \frac{4}{3} x^{2}

Multiply both sides by

3

900 - 120 x + 12 x^{2} = 900 - 60 x + 4 x^{2}

Move

4 x^{2}

to the left side

900 - 120 x + 8 x^{2} = 900 - 60 x

Move

60 x

to the left side

8 x^{2} - 60 x + 900 = 900

Move

900

to the left side

8 x^{2} - 60 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 60)^{2} - 4 \cdot 8 \cdot 0 = 60

x_{1, 2} = \frac{- ( - 60 ) \pm 60}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 60}{2 \cdot 8}, x_{2} = \frac{- ( - 60 ) - 60}{2 \cdot 8}

x = \frac{- ( - 60 ) + 60}{2 \cdot 8} : \frac{15}{2}

x = \frac{- ( - 60 ) - 60}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{15}{2}, x = 0

802.2 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

x^{2} + a x + b x + ab = 0

2 x^{2} - 5 x = 3

2 x^{2} - 5 x = 0

x^{2} + 2 x + 1 = 3

What are the solutions to the equation 300-40x+4x^2=300-20x+4/3 x^2 ?
The solutions to the equation 300-40x+4x^2=300-20x+4/3 x^2 are x= 15/2 ,x=0
Find the zeros of 300-40x+4x^2=300-20x+4/3 x^2
The zeros of 300-40x+4x^2=300-20x+4/3 x^2 are x= 15/2 ,x=0