What are the solutions to the equation x^2+ax+bx+ab=0 ?

The solutions to the equation x^2+ax+bx+ab=0 are x=-b,x=-a

Find the zeros of x^2+ax+bx+ab=0

The zeros of x^2+ax+bx+ab=0 are x=-b,x=-a

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x^{2} + a x + b x + ab = 0

x = - b, x = - a

Solution steps

x^{2} + a x + b x + ab = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + (a + b) x + ab = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( a + b ) \pm ( a + b ) ^{2} - 4 \cdot 1 \cdot ab}{2 \cdot 1}

Simplify

(a + b)^{2} - 4 \cdot 1 \cdot ab : a - b

x_{1, 2} = \frac{- ( a + b ) \pm ( a - b )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( a + b ) + a - b}{2 \cdot 1}, x_{2} = \frac{- ( a + b ) - ( a - b )}{2 \cdot 1}

x = \frac{- ( a + b ) + a - b}{2 \cdot 1} : - b

x = \frac{- ( a + b ) - ( a - b )}{2 \cdot 1} : - a

The solutions to the quadratic equation are:

x = - b, x = - a

2 x^{2} - 5 x = 3

2 x^{2} - 5 x = 0

x^{2} + 2 x + 1 = 3

x^{2} + 4 x + 8 = 0

x^{2} + 2 x + 2 = 9

What are the solutions to the equation x^2+ax+bx+ab=0 ?
The solutions to the equation x^2+ax+bx+ab=0 are x=-b,x=-a
Find the zeros of x^2+ax+bx+ab=0
The zeros of x^2+ax+bx+ab=0 are x=-b,x=-a