What are the solutions to the equation y^2=-2,7+36+8=17 ?

The solutions to the equation y^2=-2,7+36+8=17 are y=sqrt(2)i,y=-sqrt(2)i

Find the zeros of y^2=-2,7+36+8=17

The zeros of y^2=-2,7+36+8=17 are y=sqrt(2)i,y=-sqrt(2)i

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y^{2} = - 2, 7 + 36 + 8 = 17

y = 2 i, y = - 2 i

Solution steps

y^{2} = - 2, 7 + 36 + 8 = 17

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 2, y = - - 2

- 2 = 2 i

- - 2 = - 2 i

y = 2 i, y = - 2 i

139.39 = - 4.9 t^{2} + 73.92 t

2^{3} b^{2} = 2^{7}

4 x^{2} - 16 x + 16 = 4 x

x^{2} + 6 - 5 x = 0

(x - 1)^{2} - 36 = 0

What are the solutions to the equation y^2=-2,7+36+8=17 ?
The solutions to the equation y^2=-2,7+36+8=17 are y=sqrt(2)i,y=-sqrt(2)i
Find the zeros of y^2=-2,7+36+8=17
The zeros of y^2=-2,7+36+8=17 are y=sqrt(2)i,y=-sqrt(2)i