What are the solutions to the equation 0=-16x^2+7744 ?

The solutions to the equation 0=-16x^2+7744 are x=22,x=-22

Find the zeros of 0=-16x^2+7744

The zeros of 0=-16x^2+7744 are x=22,x=-22

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0 = - 16 x^{2} + 7744

x = 22, x = - 22

Solution steps

0 = - 16 x^{2} + 7744

Switch sides

- 16 x^{2} + 7744 = 0

Move

7744

to the right side

- 16 x^{2} = - 7744

Divide both sides by

- 16

x^{2} = 484

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 484, x = - 484

484 = 22

- 484 = - 22

x = 22, x = - 22

- 2 x^{2} - 8 x = 0

x, x^{2} + 12 x = - 36

(11 - 2 x) (24 - 2 x) = 114

\frac{( 15 c ^{2} - 8 c )}{3} = 4

x^{2} = x (4 - x)

What are the solutions to the equation 0=-16x^2+7744 ?
The solutions to the equation 0=-16x^2+7744 are x=22,x=-22
Find the zeros of 0=-16x^2+7744
The zeros of 0=-16x^2+7744 are x=22,x=-22