What are the solutions to the equation 2sqrt(7)x^2+19x-3sqrt(7)=0 ?

The solutions to the equation 2sqrt(7)x^2+19x-3sqrt(7)=0 are x= 1/(sqrt(7)),x=-(3sqrt(7))/2

Find the zeros of 2sqrt(7)x^2+19x-3sqrt(7)=0

The zeros of 2sqrt(7)x^2+19x-3sqrt(7)=0 are x= 1/(sqrt(7)),x=-(3sqrt(7))/2

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27 x^{2} + 19 x - 37 = 0

x = \frac{1}{7}, x = - \frac{3 7}{2}

Decimal Notation

x = 0.37796 \dots, x = - 3.96862 \dots

Solution steps

27 x^{2} + 19 x - 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 2 7 ( - 3 7 )}{2 \cdot 2 7}

1 9^{2} - 4 \cdot 27 (- 37) = 23

x_{1, 2} = \frac{- 19 \pm 23}{2 \cdot 2 7}

Separate the solutions

x_{1} = \frac{- 19 + 23}{2 \cdot 2 7}, x_{2} = \frac{- 19 - 23}{2 \cdot 2 7}

x = \frac{- 19 + 23}{2 \cdot 2 7} : \frac{1}{7}

x = \frac{- 19 - 23}{2 \cdot 2 7} : - \frac{3 7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{7}, x = - \frac{3 7}{2}

- 4 w^{2} + 16 w - 16 = 0

3 x^{2} - 36 x + 81 = 0

x^{2} - 12 = 7 x

3 x^{2} + x - \frac{1}{2} = 0

x, x^{2} y - 9 y - x^{2} + 3 = 0

What are the solutions to the equation 2sqrt(7)x^2+19x-3sqrt(7)=0 ?
The solutions to the equation 2sqrt(7)x^2+19x-3sqrt(7)=0 are x= 1/(sqrt(7)),x=-(3sqrt(7))/2
Find the zeros of 2sqrt(7)x^2+19x-3sqrt(7)=0
The zeros of 2sqrt(7)x^2+19x-3sqrt(7)=0 are x= 1/(sqrt(7)),x=-(3sqrt(7))/2