What are the solutions to the equation (3x-1)(3x+1)=0 ?

The solutions to the equation (3x-1)(3x+1)=0 are x= 1/3 ,x=-1/3

Find the zeros of (3x-1)(3x+1)=0

The zeros of (3x-1)(3x+1)=0 are x= 1/3 ,x=-1/3

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(3 x - 1) (3 x + 1) = 0

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.33333 \dots, x = - 0.33333 \dots

Solution steps

(3 x - 1) (3 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or 3 x + 1 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{3}

- 3 x^{2} + 24 x - 46

h^{2} + 9 h = 0

x^{2} - 4 = - (4 - 2 x)

x (x - 16) + 63 = 0

q, p = 2 q^{2}

What are the solutions to the equation (3x-1)(3x+1)=0 ?
The solutions to the equation (3x-1)(3x+1)=0 are x= 1/3 ,x=-1/3
Find the zeros of (3x-1)(3x+1)=0
The zeros of (3x-1)(3x+1)=0 are x= 1/3 ,x=-1/3