What are the solutions to the equation x^2+22x+101=0 ?

The solutions to the equation x^2+22x+101=0 are x=-11+2sqrt(5),x=-11-2sqrt(5)

Find the zeros of x^2+22x+101=0

The zeros of x^2+22x+101=0 are x=-11+2sqrt(5),x=-11-2sqrt(5)

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x^{2} + 22 x + 101 = 0

x = - 11 + 25, x = - 11 - 25

Decimal Notation

x = - 6.52786 \dots, x = - 15.47213 \dots

Solution steps

x^{2} + 22 x + 101 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 101}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 101 = 45

x_{1, 2} = \frac{- 22 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 22 - 4 5}{2 \cdot 1}

x = \frac{- 22 + 4 5}{2 \cdot 1} : - 11 + 25

x = \frac{- 22 - 4 5}{2 \cdot 1} : - 11 - 25

The solutions to the quadratic equation are:

x = - 11 + 25, x = - 11 - 25

- x^{2} + 3 x + 1 = - x + 1

16 + x^{2} = 49

2 x^{2} - 14 x = - 15 - x^{2}

0 = - 4.9 x^{2} + 10 x + 100

x + x - \frac{xx}{100} = 36

What are the solutions to the equation x^2+22x+101=0 ?
The solutions to the equation x^2+22x+101=0 are x=-11+2sqrt(5),x=-11-2sqrt(5)
Find the zeros of x^2+22x+101=0
The zeros of x^2+22x+101=0 are x=-11+2sqrt(5),x=-11-2sqrt(5)