What are the solutions to the equation -10x+14=x^2-5x ?

The solutions to the equation -10x+14=x^2-5x are x=2,x=-7

Find the zeros of -10x+14=x^2-5x

The zeros of -10x+14=x^2-5x are x=2,x=-7

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- 10 x + 14 = x^{2} - 5 x

x = 2, x = - 7

Solution steps

- 10 x + 14 = x^{2} - 5 x

Switch sides

x^{2} - 5 x = - 10 x + 14

Move

14

to the left side

x^{2} - 5 x - 14 = - 10 x

Move

10 x

to the left side

x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

10 x^{2} - 5 x = 2 x^{2} + 4 x

x, 3 x^{2} - 4 x - 3 = 0

11 x^{2} + 18 x + 7 = 0

2 x^{2} + x - 1081 = 0

x, x^{2} - x - 3 = 0

What are the solutions to the equation -10x+14=x^2-5x ?
The solutions to the equation -10x+14=x^2-5x are x=2,x=-7
Find the zeros of -10x+14=x^2-5x
The zeros of -10x+14=x^2-5x are x=2,x=-7