What are the solutions to the equation x^2+2x^2=1 ?

The solutions to the equation x^2+2x^2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of x^2+2x^2=1

The zeros of x^2+2x^2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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x^{2} + 2 x^{2} = 1

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

x^{2} + 2 x^{2} = 1

Add similar elements:

x^{2} + 2 x^{2} = 3 x^{2}

3 x^{2} = 1

Divide both sides by

3

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

x^{2} - 6 x + a = 0

144 a^{2} + 216 a + 81 = 0

(x - 1) (2 x + 2) = 0

0 = 18 + 6 t - 4 t^{2}

\frac{1}{4} x^{2} = - \frac{1}{2} x + 2

What are the solutions to the equation x^2+2x^2=1 ?
The solutions to the equation x^2+2x^2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of x^2+2x^2=1
The zeros of x^2+2x^2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))