What are the solutions to the equation x^2-6x+a=0 ?

The solutions to the equation x^2-6x+a=0 are x=3+sqrt(-a+9),x=3-sqrt(-a+9)

Find the zeros of x^2-6x+a=0

The zeros of x^2-6x+a=0 are x=3+sqrt(-a+9),x=3-sqrt(-a+9)

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x^{2} - 6 x + a = 0

x = 3 + - a + 9, x = 3 - - a + 9

Solution steps

x^{2} - 6 x + a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot a}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot a : 2 9 - a

x_{1, 2} = \frac{- ( - 6 ) \pm 2 9 - a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 9 - a}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 9 - a}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 9 - a}{2 \cdot 1} : 3 + - a + 9

x = \frac{- ( - 6 ) - 2 9 - a}{2 \cdot 1} : 3 - - a + 9

The solutions to the quadratic equation are:

x = 3 + - a + 9, x = 3 - - a + 9

144 a^{2} + 216 a + 81 = 0

(x - 1) (2 x + 2) = 0

0 = 18 + 6 t - 4 t^{2}

\frac{1}{4} x^{2} = - \frac{1}{2} x + 2

4 = x^{2} + 3

What are the solutions to the equation x^2-6x+a=0 ?
The solutions to the equation x^2-6x+a=0 are x=3+sqrt(-a+9),x=3-sqrt(-a+9)
Find the zeros of x^2-6x+a=0
The zeros of x^2-6x+a=0 are x=3+sqrt(-a+9),x=3-sqrt(-a+9)