What are the solutions to the equation 18x^2-21x-4=0 ?

The solutions to the equation 18x^2-21x-4=0 are x= 4/3 ,x=-1/6

Find the zeros of 18x^2-21x-4=0

The zeros of 18x^2-21x-4=0 are x= 4/3 ,x=-1/6

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18 x^{2} - 21 x - 4 = 0

x = \frac{4}{3}, x = - \frac{1}{6}

Decimal Notation

x = 1.33333 \dots, x = - 0.16666 \dots

Solution steps

18 x^{2} - 21 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 18 ( - 4 )}{2 \cdot 18}

(- 21)^{2} - 4 \cdot 18 (- 4) = 27

x_{1, 2} = \frac{- ( - 21 ) \pm 27}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 27}{2 \cdot 18}, x_{2} = \frac{- ( - 21 ) - 27}{2 \cdot 18}

x = \frac{- ( - 21 ) + 27}{2 \cdot 18} : \frac{4}{3}

x = \frac{- ( - 21 ) - 27}{2 \cdot 18} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{1}{6}

x (x + 9) = 2 x - 12

x^{2} + \frac{1}{16} = 1

8 x^{2} + 5 x - 2 = 0

x^{2} - 105 x + 1260 = 0

x^{2} - 20 x = 17

What are the solutions to the equation 18x^2-21x-4=0 ?
The solutions to the equation 18x^2-21x-4=0 are x= 4/3 ,x=-1/6
Find the zeros of 18x^2-21x-4=0
The zeros of 18x^2-21x-4=0 are x= 4/3 ,x=-1/6