What are the solutions to the equation (k-4)^2=9 ?

The solutions to the equation (k-4)^2=9 are k=7,k=1

Find the zeros of (k-4)^2=9

The zeros of (k-4)^2=9 are k=7,k=1

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(k - 4)^{2} = 9

k = 7, k = 1

Solution steps

(k - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k - 4 = 9 : k = 7

Solve

k - 4 = - 9 : k = 1

The solutions to the quadratic equation are:

k = 7, k = 1

3 x = 15 x^{2}

y^{2} - 6 y = 0

0 = 2 x^{2} - 4 x - 6

x^{2} - 6 x + n = 0

4 q^{2} - 12 q + 9 = 0

What are the solutions to the equation (k-4)^2=9 ?
The solutions to the equation (k-4)^2=9 are k=7,k=1
Find the zeros of (k-4)^2=9
The zeros of (k-4)^2=9 are k=7,k=1