What are the solutions to the equation 0=2x^2-4x-6 ?

The solutions to the equation 0=2x^2-4x-6 are x=3,x=-1

Find the zeros of 0=2x^2-4x-6

The zeros of 0=2x^2-4x-6 are x=3,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 2 x^{2} - 4 x - 6

x = 3, x = - 1

Solution steps

0 = 2 x^{2} - 4 x - 6

Switch sides

2 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 2}

x = \frac{- ( - 4 ) + 8}{2 \cdot 2} : 3

x = \frac{- ( - 4 ) - 8}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

x^{2} - 6 x + n = 0

4 q^{2} - 12 q + 9 = 0

5 t^{2} - 16 t = 16

- 32000 u^{2} + 8000 u - 500 = 0

(x + 9)^{2} = 8

What are the solutions to the equation 0=2x^2-4x-6 ?
The solutions to the equation 0=2x^2-4x-6 are x=3,x=-1
Find the zeros of 0=2x^2-4x-6
The zeros of 0=2x^2-4x-6 are x=3,x=-1