What are the solutions to the equation 4q^2-12q+9=0 ?

The solutions to the equation 4q^2-12q+9=0 are q= 3/2

Find the zeros of 4q^2-12q+9=0

The zeros of 4q^2-12q+9=0 are q= 3/2

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4 q^{2} - 12 q + 9 = 0

q = \frac{3}{2}

Decimal Notation

q = 1.5

Solution steps

4 q^{2} - 12 q + 9 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

q_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

q = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

q = \frac{3}{2}

The solution to the quadratic equation is:

q = \frac{3}{2}

5 t^{2} - 16 t = 16

- 32000 u^{2} + 8000 u - 500 = 0

(x + 9)^{2} = 8

300 = 500 - 2 q^{2}

x^{2} - 26 x + 120 = 0

What are the solutions to the equation 4q^2-12q+9=0 ?
The solutions to the equation 4q^2-12q+9=0 are q= 3/2
Find the zeros of 4q^2-12q+9=0
The zeros of 4q^2-12q+9=0 are q= 3/2