What are the solutions to the equation -32000u^2+8000u-500=0 ?

The solutions to the equation -32000u^2+8000u-500=0 are u= 1/8

Find the zeros of -32000u^2+8000u-500=0

The zeros of -32000u^2+8000u-500=0 are u= 1/8

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- 32000 u^{2} + 8000 u - 500 = 0

u = \frac{1}{8}

Decimal Notation

u = 0.125

Solution steps

- 32000 u^{2} + 8000 u - 500 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 8000 \pm 800 0 ^{2} - 4 ( - 32000 ) ( - 500 )}{2 ( - 32000 )}

800 0^{2} - 4 (- 32000) (- 500) = 0

u_{1, 2} = \frac{- 8000 \pm 0}{2 ( - 32000 )}

u = \frac{- 8000}{2 ( - 32000 )}

\frac{- 8000}{2 ( - 32000 )} = \frac{1}{8}

u = \frac{1}{8}

The solution to the quadratic equation is:

u = \frac{1}{8}

(x + 9)^{2} = 8

300 = 500 - 2 q^{2}

x^{2} - 26 x + 120 = 0

(\frac{15}{17})^{2} + x^{2} = 1

40 r^{2} + 31 r + 6 = 0

What are the solutions to the equation -32000u^2+8000u-500=0 ?
The solutions to the equation -32000u^2+8000u-500=0 are u= 1/8
Find the zeros of -32000u^2+8000u-500=0
The zeros of -32000u^2+8000u-500=0 are u= 1/8