What are the solutions to the equation x^2-26x+120=0 ?

The solutions to the equation x^2-26x+120=0 are x=20,x=6

Find the zeros of x^2-26x+120=0

The zeros of x^2-26x+120=0 are x=20,x=6

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x^{2} - 26 x + 120 = 0

x = 20, x = 6

Solution steps

x^{2} - 26 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 120}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 120 = 14

x_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 1}

x = \frac{- ( - 26 ) + 14}{2 \cdot 1} : 20

x = \frac{- ( - 26 ) - 14}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 20, x = 6

(\frac{15}{17})^{2} + x^{2} = 1

40 r^{2} + 31 r + 6 = 0

F^{2} = 1 0^{2} + 1 0^{2} + 2 \cdot 10 \cdot 10 \cdot \frac{1}{2}

x, x^{2} + y^{2} - 6 x - 6 y + 27 = 0

3 g^{2} - 24 g + 27 = 0

What are the solutions to the equation x^2-26x+120=0 ?
The solutions to the equation x^2-26x+120=0 are x=20,x=6
Find the zeros of x^2-26x+120=0
The zeros of x^2-26x+120=0 are x=20,x=6