What are the solutions to the equation 576x^2-612x+36=0 ?

The solutions to the equation 576x^2-612x+36=0 are x=1,x= 1/16

Find the zeros of 576x^2-612x+36=0

The zeros of 576x^2-612x+36=0 are x=1,x= 1/16

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576 x^{2} - 612 x + 36 = 0

x = 1, x = \frac{1}{16}

Decimal Notation

x = 1, x = 0.0625

Solution steps

576 x^{2} - 612 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 612 ) \pm ( - 612 ) ^{2} - 4 \cdot 576 \cdot 36}{2 \cdot 576}

(- 612)^{2} - 4 \cdot 576 \cdot 36 = 540

x_{1, 2} = \frac{- ( - 612 ) \pm 540}{2 \cdot 576}

Separate the solutions

x_{1} = \frac{- ( - 612 ) + 540}{2 \cdot 576}, x_{2} = \frac{- ( - 612 ) - 540}{2 \cdot 576}

x = \frac{- ( - 612 ) + 540}{2 \cdot 576} : 1

x = \frac{- ( - 612 ) - 540}{2 \cdot 576} : \frac{1}{16}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{16}

8 p^{2} + p = 9

a x^{2} + b x c = 0

3 x^{2} - 8 = 19

k^{2} = 121

x, x^{2} = 1 + y

What are the solutions to the equation 576x^2-612x+36=0 ?
The solutions to the equation 576x^2-612x+36=0 are x=1,x= 1/16
Find the zeros of 576x^2-612x+36=0
The zeros of 576x^2-612x+36=0 are x=1,x= 1/16