What are the solutions to the equation 91-q^2=1+q ?

The solutions to the equation 91-q^2=1+q are q=-10,q=9

Find the zeros of 91-q^2=1+q

The zeros of 91-q^2=1+q are q=-10,q=9

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91 - q^{2} = 1 + q

q = - 10, q = 9

Solution steps

91 - q^{2} = 1 + q

Move

q

to the left side

91 - q^{2} - q = 1

Move

1

to the left side

- q^{2} - q + 90 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 90}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 90 = 19

q_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 1 ) + 19}{2 ( - 1 )}, q_{2} = \frac{- ( - 1 ) - 19}{2 ( - 1 )}

q = \frac{- ( - 1 ) + 19}{2 ( - 1 )} : - 10

q = \frac{- ( - 1 ) - 19}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

q = - 10, q = 9

(x - 8)^{2} = 2

x^{2} + 1 = 3 x + 1

3 x - 5 x^{2} + 8 x = 7 + 5 x

5 x^{2} + 7 x + 9 = 0

x^{2} + 14 x + 49

What are the solutions to the equation 91-q^2=1+q ?
The solutions to the equation 91-q^2=1+q are q=-10,q=9
Find the zeros of 91-q^2=1+q
The zeros of 91-q^2=1+q are q=-10,q=9