What are the solutions to the equation x^2+1=3x+1 ?

The solutions to the equation x^2+1=3x+1 are x=3,x=0

Find the zeros of x^2+1=3x+1

The zeros of x^2+1=3x+1 are x=3,x=0

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x^{2} + 1 = 3 x + 1

x = 3, x = 0

Solution steps

x^{2} + 1 = 3 x + 1

Move

1

to the left side

x^{2} = 3 x

Move

3 x

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

3 x - 5 x^{2} + 8 x = 7 + 5 x

5 x^{2} + 7 x + 9 = 0

x^{2} + 14 x + 49

- 4 x^{2} - 4 x - 3 = 0

3 y^{2} + 2 = 0

What are the solutions to the equation x^2+1=3x+1 ?
The solutions to the equation x^2+1=3x+1 are x=3,x=0
Find the zeros of x^2+1=3x+1
The zeros of x^2+1=3x+1 are x=3,x=0