What are the solutions to the equation 6+x-x^2=x^2 ?

The solutions to the equation 6+x-x^2=x^2 are x=-3/2 ,x=2

Find the zeros of 6+x-x^2=x^2

The zeros of 6+x-x^2=x^2 are x=-3/2 ,x=2

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6 + x - x^{2} = x^{2}

x = - \frac{3}{2}, x = 2

Decimal Notation

x = - 1.5, x = 2

Solution steps

6 + x - x^{2} = x^{2}

Move

x^{2}

to the left side

6 + x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 2 )}, x_{2} = \frac{- 1 - 7}{2 ( - 2 )}

x = \frac{- 1 + 7}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 1 - 7}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 2

(3 x + 4)^{2} = 8

m (m + 2) = - 3 - 2 m

4 x^{2} - 24 x + 42

4 + (x - 2)^{2} = x (4 - x)

4.9 x^{2} - 30.88 x - 4 = 0

What are the solutions to the equation 6+x-x^2=x^2 ?
The solutions to the equation 6+x-x^2=x^2 are x=-3/2 ,x=2
Find the zeros of 6+x-x^2=x^2
The zeros of 6+x-x^2=x^2 are x=-3/2 ,x=2