What are the solutions to the equation (3x+4)^2=8 ?

The solutions to the equation (3x+4)^2=8 are x=(2sqrt(2)-4)/3 ,x=(-2sqrt(2)-4)/3

Find the zeros of (3x+4)^2=8

The zeros of (3x+4)^2=8 are x=(2sqrt(2)-4)/3 ,x=(-2sqrt(2)-4)/3

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(3 x + 4)^{2} = 8

x = \frac{2 2 - 4}{3}, x = \frac{- 2 2 - 4}{3}

Decimal Notation

x = - 0.39052 \dots, x = - 2.27614 \dots

Solution steps

(3 x + 4)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 8 : x = \frac{2 2 - 4}{3}

Solve

3 x + 4 = - 8 : x = \frac{- 2 2 - 4}{3}

The solutions to the quadratic equation are:

x = \frac{2 2 - 4}{3}, x = \frac{- 2 2 - 4}{3}

m (m + 2) = - 3 - 2 m

4 x^{2} - 24 x + 42

4 + (x - 2)^{2} = x (4 - x)

4.9 x^{2} - 30.88 x - 4 = 0

t^{2} - 6 t - 27 = 0

What are the solutions to the equation (3x+4)^2=8 ?
The solutions to the equation (3x+4)^2=8 are x=(2sqrt(2)-4)/3 ,x=(-2sqrt(2)-4)/3
Find the zeros of (3x+4)^2=8
The zeros of (3x+4)^2=8 are x=(2sqrt(2)-4)/3 ,x=(-2sqrt(2)-4)/3