What are the solutions to the equation m(m+2)=-3-2m ?

The solutions to the equation m(m+2)=-3-2m are m=-1,m=-3

Find the zeros of m(m+2)=-3-2m

The zeros of m(m+2)=-3-2m are m=-1,m=-3

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m (m + 2) = - 3 - 2 m

m = - 1, m = - 3

Solution steps

m (m + 2) = - 3 - 2 m

Expand

m (m + 2) : m^{2} + 2 m

m^{2} + 2 m = - 3 - 2 m

Move

2 m

to the left side

m^{2} + 4 m = - 3

Move

3

to the left side

m^{2} + 4 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

m_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2}{2 \cdot 1}, m_{2} = \frac{- 4 - 2}{2 \cdot 1}

m = \frac{- 4 + 2}{2 \cdot 1} : - 1

m = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = - 1, m = - 3

4 x^{2} - 24 x + 42

4 + (x - 2)^{2} = x (4 - x)

4.9 x^{2} - 30.88 x - 4 = 0

t^{2} - 6 t - 27 = 0

x^{2} + 14 x - 10 = 5

What are the solutions to the equation m(m+2)=-3-2m ?
The solutions to the equation m(m+2)=-3-2m are m=-1,m=-3
Find the zeros of m(m+2)=-3-2m
The zeros of m(m+2)=-3-2m are m=-1,m=-3