What are the solutions to the equation t^2-6t-27=0 ?

The solutions to the equation t^2-6t-27=0 are t=9,t=-3

Find the zeros of t^2-6t-27=0

The zeros of t^2-6t-27=0 are t=9,t=-3

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t^{2} - 6 t - 27 = 0

t = 9, t = - 3

Solution steps

t^{2} - 6 t - 27 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 27) = 12

t_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 1}

t = \frac{- ( - 6 ) + 12}{2 \cdot 1} : 9

t = \frac{- ( - 6 ) - 12}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

t = 9, t = - 3

x^{2} + 14 x - 10 = 5

5 d (d + 1) + 6 = 0

x, x^{2} + 5 x - 6 = 0

4 x^{2} + 12 x = 0

8 = 2 x (x - 3)

What are the solutions to the equation t^2-6t-27=0 ?
The solutions to the equation t^2-6t-27=0 are t=9,t=-3
Find the zeros of t^2-6t-27=0
The zeros of t^2-6t-27=0 are t=9,t=-3