What are the solutions to the equation solvefor x,y^{-1}=x^2 ?

The solutions to the equation solvefor x,y^{-1}=x^2 are x= 1/(sqrt(y)),x=-1/(sqrt(y))

Find the zeros of solvefor x,y^{-1}=x^2

The zeros of solvefor x,y^{-1}=x^2 are x= 1/(sqrt(y)),x=-1/(sqrt(y))

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solve for

x, y^{- 1} = x^{2}

x = \frac{1}{y}, x = - \frac{1}{y}

Solution steps

y^{- 1} = x^{2}

Switch sides

x^{2} = y^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{2} = \frac{1}{y}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{y}, x = - \frac{1}{y}

Simplify

\frac{1}{y} : \frac{1}{y}

Simplify

- \frac{1}{y} : - \frac{1}{y}

x = \frac{1}{y}, x = - \frac{1}{y}

x^{2} + 17 x + 52 = 0

3 x^{2} + 2 x + 1

10 m^{2} + 2 = 152

x^{2} - 25 x + 150 = 0

2 x^{2} + 9 x - 16 = 0

What are the solutions to the equation solvefor x,y^{-1}=x^2 ?
The solutions to the equation solvefor x,y^{-1}=x^2 are x= 1/(sqrt(y)),x=-1/(sqrt(y))
Find the zeros of solvefor x,y^{-1}=x^2
The zeros of solvefor x,y^{-1}=x^2 are x= 1/(sqrt(y)),x=-1/(sqrt(y))