What are the solutions to the equation 36.12+2.2^2=c^2 ?

The solutions to the equation 36.12+2.2^2=c^2 are c= 32/5 ,c=-32/5

Find the zeros of 36.12+2.2^2=c^2

The zeros of 36.12+2.2^2=c^2 are c= 32/5 ,c=-32/5

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36.12 + 2. 2^{2} = c^{2}

c = \frac{32}{5}, c = - \frac{32}{5}

Decimal Notation

c = 6.4, c = - 6.4

Solution steps

36.12 + 2. 2^{2} = c^{2}

Switch sides

c^{2} = 36.12 + 2. 2^{2}

Simplify

36.12 + 2. 2^{2} : 40.96

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 40.96, c = - 40.96

40.96 = \frac{32}{5}

- 40.96 = - \frac{32}{5}

c = \frac{32}{5}, c = - \frac{32}{5}

(2 x - 1) (x + 6) = 0

x^{2} - 12 x + 11

16 x^{2} = (A + B) x^{2} + x (10 A - 10 B - C) + 25 A - 75 B - 15 C

7 x^{2} + 14 x + 3 = 0

x^{2} - 25 x = - 100

What are the solutions to the equation 36.12+2.2^2=c^2 ?
The solutions to the equation 36.12+2.2^2=c^2 are c= 32/5 ,c=-32/5
Find the zeros of 36.12+2.2^2=c^2
The zeros of 36.12+2.2^2=c^2 are c= 32/5 ,c=-32/5