What are the solutions to the equation (2x-1)(x+6)=0 ?

The solutions to the equation (2x-1)(x+6)=0 are x= 1/2 ,x=-6

Find the zeros of (2x-1)(x+6)=0

The zeros of (2x-1)(x+6)=0 are x= 1/2 ,x=-6

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(2 x - 1) (x + 6) = 0

x = \frac{1}{2}, x = - 6

Decimal Notation

x = 0.5, x = - 6

Solution steps

(2 x - 1) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 6 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 6

x^{2} - 12 x + 11

16 x^{2} = (A + B) x^{2} + x (10 A - 10 B - C) + 25 A - 75 B - 15 C

7 x^{2} + 14 x + 3 = 0

x^{2} - 25 x = - 100

x^{2} = 45 - 4 x

What are the solutions to the equation (2x-1)(x+6)=0 ?
The solutions to the equation (2x-1)(x+6)=0 are x= 1/2 ,x=-6
Find the zeros of (2x-1)(x+6)=0
The zeros of (2x-1)(x+6)=0 are x= 1/2 ,x=-6