What are the solutions to the equation 7x^2+14x+3=0 ?

The solutions to the equation 7x^2+14x+3=0 are x=(-7+2sqrt(7))/7 ,x=-(sqrt(7)+2)/(sqrt(7))

Find the zeros of 7x^2+14x+3=0

The zeros of 7x^2+14x+3=0 are x=(-7+2sqrt(7))/7 ,x=-(sqrt(7)+2)/(sqrt(7))

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7 x^{2} + 14 x + 3 = 0

x = \frac{- 7 + 2 7}{7}, x = - \frac{7 + 2}{7}

Decimal Notation

x = - 0.24407 \dots, x = - 1.75592 \dots

Solution steps

7 x^{2} + 14 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

1 4^{2} - 4 \cdot 7 \cdot 3 = 47

x_{1, 2} = \frac{- 14 \pm 4 7}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 14 + 4 7}{2 \cdot 7}, x_{2} = \frac{- 14 - 4 7}{2 \cdot 7}

x = \frac{- 14 + 4 7}{2 \cdot 7} : \frac{- 7 + 2 7}{7}

x = \frac{- 14 - 4 7}{2 \cdot 7} : - \frac{7 + 2}{7}

The solutions to the quadratic equation are:

x = \frac{- 7 + 2 7}{7}, x = - \frac{7 + 2}{7}

x^{2} - 25 x = - 100

x^{2} = 45 - 4 x

(x - 3) (x + 7) = 11

2 x^{2} + 3 x - 20 = 0

2 x^{2} - 12 x + 4 = 0

What are the solutions to the equation 7x^2+14x+3=0 ?
The solutions to the equation 7x^2+14x+3=0 are x=(-7+2sqrt(7))/7 ,x=-(sqrt(7)+2)/(sqrt(7))
Find the zeros of 7x^2+14x+3=0
The zeros of 7x^2+14x+3=0 are x=(-7+2sqrt(7))/7 ,x=-(sqrt(7)+2)/(sqrt(7))