What are the solutions to the equation 8x^2-55x+42=0 ?

The solutions to the equation 8x^2-55x+42=0 are x=6,x= 7/8

Find the zeros of 8x^2-55x+42=0

The zeros of 8x^2-55x+42=0 are x=6,x= 7/8

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8 x^{2} - 55 x + 42 = 0

x = 6, x = \frac{7}{8}

Decimal Notation

x = 6, x = 0.875

Solution steps

8 x^{2} - 55 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 55 ) \pm ( - 55 ) ^{2} - 4 \cdot 8 \cdot 42}{2 \cdot 8}

(- 55)^{2} - 4 \cdot 8 \cdot 42 = 41

x_{1, 2} = \frac{- ( - 55 ) \pm 41}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 55 ) + 41}{2 \cdot 8}, x_{2} = \frac{- ( - 55 ) - 41}{2 \cdot 8}

x = \frac{- ( - 55 ) + 41}{2 \cdot 8} : 6

x = \frac{- ( - 55 ) - 41}{2 \cdot 8} : \frac{7}{8}

The solutions to the quadratic equation are:

x = 6, x = \frac{7}{8}

t^{2} + 2 t + 3 = 0

3 y^{2} - 17 y + 10 = 0

t^{2} + 2 t + 2 = 0

2 x^{2} - 6 = - 168

y, \frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

What are the solutions to the equation 8x^2-55x+42=0 ?
The solutions to the equation 8x^2-55x+42=0 are x=6,x= 7/8
Find the zeros of 8x^2-55x+42=0
The zeros of 8x^2-55x+42=0 are x=6,x= 7/8