What are the solutions to the equation t^2+2t+3=0 ?

The solutions to the equation t^2+2t+3=0 are t=-1+sqrt(2)i,t=-1-sqrt(2)i

Find the zeros of t^2+2t+3=0

The zeros of t^2+2t+3=0 are t=-1+sqrt(2)i,t=-1-sqrt(2)i

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t^{2} + 2 t + 3 = 0

t = - 1 + 2 i, t = - 1 - 2 i

Solution steps

t^{2} + 2 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

t_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, t_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

t = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

t = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

t = - 1 + 2 i, t = - 1 - 2 i

3 y^{2} - 17 y + 10 = 0

t^{2} + 2 t + 2 = 0

2 x^{2} - 6 = - 168

y, \frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

x (x - 15) + 54 = 0

What are the solutions to the equation t^2+2t+3=0 ?
The solutions to the equation t^2+2t+3=0 are t=-1+sqrt(2)i,t=-1-sqrt(2)i
Find the zeros of t^2+2t+3=0
The zeros of t^2+2t+3=0 are t=-1+sqrt(2)i,t=-1-sqrt(2)i