What are the solutions to the equation 8x^2-38x+35=0 ?

The solutions to the equation 8x^2-38x+35=0 are x= 7/2 ,x= 5/4

Find the zeros of 8x^2-38x+35=0

The zeros of 8x^2-38x+35=0 are x= 7/2 ,x= 5/4

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8 x^{2} - 38 x + 35 = 0

x = \frac{7}{2}, x = \frac{5}{4}

Decimal Notation

x = 3.5, x = 1.25

Solution steps

8 x^{2} - 38 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 8 \cdot 35}{2 \cdot 8}

(- 38)^{2} - 4 \cdot 8 \cdot 35 = 18

x_{1, 2} = \frac{- ( - 38 ) \pm 18}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 38 ) + 18}{2 \cdot 8}, x_{2} = \frac{- ( - 38 ) - 18}{2 \cdot 8}

x = \frac{- ( - 38 ) + 18}{2 \cdot 8} : \frac{7}{2}

x = \frac{- ( - 38 ) - 18}{2 \cdot 8} : \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{5}{4}

3 X^{2} - 48 = 0

- 6 x^{2} + 9 = - 3 x^{2} + 6

v, \frac{0.5 v ^{2}}{1} = 350

9 x^{2} + 6 x - 48 = 0

x^{2} - 16 x + 64 = 0

What are the solutions to the equation 8x^2-38x+35=0 ?
The solutions to the equation 8x^2-38x+35=0 are x= 7/2 ,x= 5/4
Find the zeros of 8x^2-38x+35=0
The zeros of 8x^2-38x+35=0 are x= 7/2 ,x= 5/4