What are the solutions to the equation 9x^2+6x-48=0 ?

The solutions to the equation 9x^2+6x-48=0 are x=2,x=-8/3

Find the zeros of 9x^2+6x-48=0

The zeros of 9x^2+6x-48=0 are x=2,x=-8/3

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9 x^{2} + 6 x - 48 = 0

x = 2, x = - \frac{8}{3}

Decimal Notation

x = 2, x = - 2.66666 \dots

Solution steps

9 x^{2} + 6 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 48 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 48) = 42

x_{1, 2} = \frac{- 6 \pm 42}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 42}{2 \cdot 9}, x_{2} = \frac{- 6 - 42}{2 \cdot 9}

x = \frac{- 6 + 42}{2 \cdot 9} : 2

x = \frac{- 6 - 42}{2 \cdot 9} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{8}{3}

x^{2} - 16 x + 64 = 0

x^{2} - 0.4 x + 4.04 = 0

x^{2} + 1.388 \cdot 1 0^{- 5} x - 8.51 \cdot 1 0^{- 17} = 0

6 x - 3 x^{2} - 3 = 0

- 0.5 x^{2} + 80 x - 250 = 0

What are the solutions to the equation 9x^2+6x-48=0 ?
The solutions to the equation 9x^2+6x-48=0 are x=2,x=-8/3
Find the zeros of 9x^2+6x-48=0
The zeros of 9x^2+6x-48=0 are x=2,x=-8/3