What are the solutions to the equation -6x^2+9=-3x^2+6 ?

The solutions to the equation -6x^2+9=-3x^2+6 are x=1,x=-1

Find the zeros of -6x^2+9=-3x^2+6

The zeros of -6x^2+9=-3x^2+6 are x=1,x=-1

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- 6 x^{2} + 9 = - 3 x^{2} + 6

x = 1, x = - 1

Solution steps

- 6 x^{2} + 9 = - 3 x^{2} + 6

Move

9

to the right side

- 6 x^{2} = - 3 x^{2} - 3

Move

3 x^{2}

to the left side

- 3 x^{2} = - 3

Divide both sides by

- 3

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

v, \frac{0.5 v ^{2}}{1} = 350

9 x^{2} + 6 x - 48 = 0

x^{2} - 16 x + 64 = 0

x^{2} - 0.4 x + 4.04 = 0

x^{2} + 1.388 \cdot 1 0^{- 5} x - 8.51 \cdot 1 0^{- 17} = 0

What are the solutions to the equation -6x^2+9=-3x^2+6 ?
The solutions to the equation -6x^2+9=-3x^2+6 are x=1,x=-1
Find the zeros of -6x^2+9=-3x^2+6
The zeros of -6x^2+9=-3x^2+6 are x=1,x=-1