What are the solutions to the equation completesquare m^2-12m+26=0 ?

The solutions to the equation completesquare m^2-12m+26=0 are m=sqrt(10)+6,m=-sqrt(10)+6

Find the zeros of completesquare m^2-12m+26=0

The zeros of completesquare m^2-12m+26=0 are m=sqrt(10)+6,m=-sqrt(10)+6

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m^{2} - 12 m + 26 = 0

m = 10 + 6, m = - 10 + 6

Decimal Notation

m = 9.16227 \dots, m = 2.83772 \dots

Solution steps

m^{2} - 12 m + 26 = 0

Move

26

to the right side

m^{2} - 12 m = - 26

Rewrite in the form

(x + a)^{2} = b

(m - 6)^{2} = 10

For

the solutions are

f (x) = a, - a

Solve

m - 6 = 10 : m = 10 + 6

Solve

m - 6 = - 10 : m = - 10 + 6

The solutions to the quadratic equation are:

m = 10 + 6, m = - 10 + 6

λ^{2} - 5 λ - 6 = 0

3 x^{2} - 1 = - 8 x

x, x^{2} - 12 x + 59 = 0

(y - 3) (y - 2) = 6 (y - 3)

3 n^{2} + 7 n - 10 = 12

What are the solutions to the equation completesquare m^2-12m+26=0 ?
The solutions to the equation completesquare m^2-12m+26=0 are m=sqrt(10)+6,m=-sqrt(10)+6
Find the zeros of completesquare m^2-12m+26=0
The zeros of completesquare m^2-12m+26=0 are m=sqrt(10)+6,m=-sqrt(10)+6