What are the solutions to the equation z^2-50z=0 ?

The solutions to the equation z^2-50z=0 are z=50,z=0

Find the zeros of z^2-50z=0

The zeros of z^2-50z=0 are z=50,z=0

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z^{2} - 50 z = 0

z = 50, z = 0

Solution steps

z^{2} - 50 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 50)^{2} - 4 \cdot 1 \cdot 0 = 50

z_{1, 2} = \frac{- ( - 50 ) \pm 50}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 50 ) + 50}{2 \cdot 1}, z_{2} = \frac{- ( - 50 ) - 50}{2 \cdot 1}

z = \frac{- ( - 50 ) + 50}{2 \cdot 1} : 50

z = \frac{- ( - 50 ) - 50}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

z = 50, z = 0

a = \frac{1}{2} r^{2} b

(x + 3) x = (6 - x) 2 x

3 x^{2} + x = - 2

1 + x + x^{2} = a (1 + x) + b \cdot (1 + x^{2}) + c \cdot (x + x^{2})

x, 16 x^{2} - 24 x y + 9 y^{2} - 30 x - 40 y = 0

What are the solutions to the equation z^2-50z=0 ?
The solutions to the equation z^2-50z=0 are z=50,z=0
Find the zeros of z^2-50z=0
The zeros of z^2-50z=0 are z=50,z=0