What are the solutions to the equation x^2-x-35=x+1 ?

The solutions to the equation x^2-x-35=x+1 are x=1+sqrt(37),x=1-sqrt(37)

Find the zeros of x^2-x-35=x+1

The zeros of x^2-x-35=x+1 are x=1+sqrt(37),x=1-sqrt(37)

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x^{2} - x - 35 = x + 1

x = 1 + 37, x = 1 - 37

Decimal Notation

x = 7.08276 \dots, x = - 5.08276 \dots

Solution steps

x^{2} - x - 35 = x + 1

Move

1

to the left side

x^{2} - x - 36 = x

Move

x

to the left side

x^{2} - 2 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 36) = 237

x_{1, 2} = \frac{- ( - 2 ) \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 37}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 37}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 37}{2 \cdot 1} : 1 + 37

x = \frac{- ( - 2 ) - 2 37}{2 \cdot 1} : 1 - 37

The solutions to the quadratic equation are:

x = 1 + 37, x = 1 - 37

(2 x + 1) (x - 6) = 0

- 6 x^{2} - 36 x + 42 = 0

- x^{2} \cdot 25 = 0

- 0.1 x^{2} - x + 40 = 0.1 x^{2} + 2 x + 20

4 x^{2} - 6 x + 9 = 0

What are the solutions to the equation x^2-x-35=x+1 ?
The solutions to the equation x^2-x-35=x+1 are x=1+sqrt(37),x=1-sqrt(37)
Find the zeros of x^2-x-35=x+1
The zeros of x^2-x-35=x+1 are x=1+sqrt(37),x=1-sqrt(37)