What are the solutions to the equation (2x+1)(x-6)=0 ?

The solutions to the equation (2x+1)(x-6)=0 are x=-1/2 ,x=6

Find the zeros of (2x+1)(x-6)=0

The zeros of (2x+1)(x-6)=0 are x=-1/2 ,x=6

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(2 x + 1) (x - 6) = 0

x = - \frac{1}{2}, x = 6

Decimal Notation

x = - 0.5, x = 6

Solution steps

(2 x + 1) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x - 6 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 6

- 6 x^{2} - 36 x + 42 = 0

- x^{2} \cdot 25 = 0

- 0.1 x^{2} - x + 40 = 0.1 x^{2} + 2 x + 20

4 x^{2} - 6 x + 9 = 0

- 2 x^{2} + 4 x + 3 = 0

What are the solutions to the equation (2x+1)(x-6)=0 ?
The solutions to the equation (2x+1)(x-6)=0 are x=-1/2 ,x=6
Find the zeros of (2x+1)(x-6)=0
The zeros of (2x+1)(x-6)=0 are x=-1/2 ,x=6