What are the solutions to the equation 7x^2+10x=3x^2-2x ?

The solutions to the equation 7x^2+10x=3x^2-2x are x=0,x=-3

Find the zeros of 7x^2+10x=3x^2-2x

The zeros of 7x^2+10x=3x^2-2x are x=0,x=-3

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7 x^{2} + 10 x = 3 x^{2} - 2 x

x = 0, x = - 3

Solution steps

7 x^{2} + 10 x = 3 x^{2} - 2 x

Move

2 x

to the left side

7 x^{2} + 12 x = 3 x^{2}

Move

3 x^{2}

to the left side

4 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 4}, x_{2} = \frac{- 12 - 12}{2 \cdot 4}

x = \frac{- 12 + 12}{2 \cdot 4} : 0

x = \frac{- 12 - 12}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

8 z = - 8 z^{2} - 2

9 x = - 5 x^{2} + 2

(4 - 2 t)^{2} + (- 1 + t)^{2} + (2 - t)^{2} = 9

21 x^{2} + 21 x - 252 = 0

4 y^{2} = 28 y

What are the solutions to the equation 7x^2+10x=3x^2-2x ?
The solutions to the equation 7x^2+10x=3x^2-2x are x=0,x=-3
Find the zeros of 7x^2+10x=3x^2-2x
The zeros of 7x^2+10x=3x^2-2x are x=0,x=-3