What are the solutions to the equation 8z=-8z^2-2 ?

The solutions to the equation 8z=-8z^2-2 are z=-1/2

Find the zeros of 8z=-8z^2-2

The zeros of 8z=-8z^2-2 are z=-1/2

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8 z = - 8 z^{2} - 2

z = - \frac{1}{2}

Decimal Notation

z = - 0.5

Solution steps

8 z = - 8 z^{2} - 2

Switch sides

- 8 z^{2} - 2 = 8 z

Move

8 z

to the left side

- 8 z^{2} - 2 - 8 z = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 z^{2} - 8 z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 8 ) ( - 2 )}{2 ( - 8 )}

(- 8)^{2} - 4 (- 8) (- 2) = 0

z_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 ( - 8 )}

z = \frac{- ( - 8 )}{2 ( - 8 )}

\frac{- ( - 8 )}{2 ( - 8 )} = - \frac{1}{2}

z = - \frac{1}{2}

The solution to the quadratic equation is:

z = - \frac{1}{2}

9 x = - 5 x^{2} + 2

(4 - 2 t)^{2} + (- 1 + t)^{2} + (2 - t)^{2} = 9

21 x^{2} + 21 x - 252 = 0

4 y^{2} = 28 y

x^{2} + 2 x - 195 = 0

What are the solutions to the equation 8z=-8z^2-2 ?
The solutions to the equation 8z=-8z^2-2 are z=-1/2
Find the zeros of 8z=-8z^2-2
The zeros of 8z=-8z^2-2 are z=-1/2