What are the solutions to the equation 4y^2=28y ?

The solutions to the equation 4y^2=28y are y=0,y=7

Find the zeros of 4y^2=28y

The zeros of 4y^2=28y are y=0,y=7

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4 y^{2} = 28 y

y = 0, y = 7

Solution steps

4 y^{2} = 28 y

Move

28 y

to the left side

4 y^{2} - 28 y = 0

Factor

4 y^{2} - 28 y : 4 y (y - 7)

4 y (y - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - 7 = 0

Solve

y - 7 = 0 : y = 7

The solutions to the quadratic equation are:

y = 0, y = 7

x^{2} + 2 x - 195 = 0

- 8 x^{2} - x - 2 = 0

12 x^{2} + 6 x + 11 = 0

35 k^{2} - 22 k + 7 = 4

x, f = k - 5 k + 1 x^{2} - 20

What are the solutions to the equation 4y^2=28y ?
The solutions to the equation 4y^2=28y are y=0,y=7
Find the zeros of 4y^2=28y
The zeros of 4y^2=28y are y=0,y=7