What are the solutions to the equation x^2+2x-195=0 ?

The solutions to the equation x^2+2x-195=0 are x=13,x=-15

Find the zeros of x^2+2x-195=0

The zeros of x^2+2x-195=0 are x=13,x=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x - 195 = 0

x = 13, x = - 15

Solution steps

x^{2} + 2 x - 195 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 195 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 195) = 28

x_{1, 2} = \frac{- 2 \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 28}{2 \cdot 1}, x_{2} = \frac{- 2 - 28}{2 \cdot 1}

x = \frac{- 2 + 28}{2 \cdot 1} : 13

x = \frac{- 2 - 28}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 13, x = - 15

- 8 x^{2} - x - 2 = 0

12 x^{2} + 6 x + 11 = 0

35 k^{2} - 22 k + 7 = 4

x, f = k - 5 k + 1 x^{2} - 20

6 x^{2} + 24 x - 30 = 810

What are the solutions to the equation x^2+2x-195=0 ?
The solutions to the equation x^2+2x-195=0 are x=13,x=-15
Find the zeros of x^2+2x-195=0
The zeros of x^2+2x-195=0 are x=13,x=-15