What are the solutions to the equation 12x^2+6x+11=0 ?

The solutions to the equation 12x^2+6x+11=0 are x=-1/4+i(sqrt(123))/(12),x=-1/4-i(sqrt(123))/(12)

Find the zeros of 12x^2+6x+11=0

The zeros of 12x^2+6x+11=0 are x=-1/4+i(sqrt(123))/(12),x=-1/4-i(sqrt(123))/(12)

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12 x^{2} + 6 x + 11 = 0

x = - \frac{1}{4} + i \frac{123}{12}, x = - \frac{1}{4} - i \frac{123}{12}

Solution steps

12 x^{2} + 6 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 12 \cdot 11}{2 \cdot 12}

Simplify

6^{2} - 4 \cdot 12 \cdot 11 : 2123 i

x_{1, 2} = \frac{- 6 \pm 2 123 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 6 + 2 123 i}{2 \cdot 12}, x_{2} = \frac{- 6 - 2 123 i}{2 \cdot 12}

x = \frac{- 6 + 2 123 i}{2 \cdot 12} : - \frac{1}{4} + i \frac{123}{12}

x = \frac{- 6 - 2 123 i}{2 \cdot 12} : - \frac{1}{4} - i \frac{123}{12}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{123}{12}, x = - \frac{1}{4} - i \frac{123}{12}

35 k^{2} - 22 k + 7 = 4

x, f = k - 5 k + 1 x^{2} - 20

6 x^{2} + 24 x - 30 = 810

x^{2} - 15 x = 11 - 5 x

c^{2} = 6^{2} + 5^{2}

What are the solutions to the equation 12x^2+6x+11=0 ?
The solutions to the equation 12x^2+6x+11=0 are x=-1/4+i(sqrt(123))/(12),x=-1/4-i(sqrt(123))/(12)
Find the zeros of 12x^2+6x+11=0
The zeros of 12x^2+6x+11=0 are x=-1/4+i(sqrt(123))/(12),x=-1/4-i(sqrt(123))/(12)