What are the solutions to the equation solvefor x,z=4x^2+y^2+4 ?

The solutions to the equation solvefor x,z=4x^2+y^2+4 are x=(sqrt(z-y^2-4))/2 ,x=-(sqrt(z-y^2-4))/2

Find the zeros of solvefor x,z=4x^2+y^2+4

The zeros of solvefor x,z=4x^2+y^2+4 are x=(sqrt(z-y^2-4))/2 ,x=-(sqrt(z-y^2-4))/2

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solve for

x, z = 4 x^{2} + y^{2} + 4

x = \frac{z - y ^{2} - 4}{2}, x = - \frac{z - y ^{2} - 4}{2}

Solution steps

z = 4 x^{2} + y^{2} + 4

Switch sides

4 x^{2} + y^{2} + 4 = z

Move

y^{2}

to the right side

4 x^{2} + 4 = z - y^{2}

Move

4

to the right side

4 x^{2} = z - y^{2} - 4

Divide both sides by

4

x^{2} = \frac{z - y ^{2} - 4}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{z - y ^{2} - 4}{4}, x = - \frac{z - y ^{2} - 4}{4}

Simplify

\frac{z - y ^{2} - 4}{4} : \frac{z - y ^{2} - 4}{2}

Simplify

- \frac{z - y ^{2} - 4}{4} : - \frac{z - y ^{2} - 4}{2}

x = \frac{z - y ^{2} - 4}{2}, x = - \frac{z - y ^{2} - 4}{2}

x^{2} - 8 = 41

x^{2} - 10 x = - 29

x^{2} + 8 x - 24 = 3 x

x, 3 x^{2} + 3 y^{2} + 9 x - 3 y + 21 = 0

- 6 x^{2} - 2 x + 77 = - 7 x^{2} + 6 x + 3

What are the solutions to the equation solvefor x,z=4x^2+y^2+4 ?
The solutions to the equation solvefor x,z=4x^2+y^2+4 are x=(sqrt(z-y^2-4))/2 ,x=-(sqrt(z-y^2-4))/2
Find the zeros of solvefor x,z=4x^2+y^2+4
The zeros of solvefor x,z=4x^2+y^2+4 are x=(sqrt(z-y^2-4))/2 ,x=-(sqrt(z-y^2-4))/2