What are the solutions to the equation 2x^2-7*=0 ?

The solutions to the equation 2x^2-7*=0 are x=sqrt(7/2),x=-sqrt(7/2)

Find the zeros of 2x^2-7*=0

The zeros of 2x^2-7*=0 are x=sqrt(7/2),x=-sqrt(7/2)

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2 x^{2} - 7 \cdot = 0

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.87082 \dots, x = - 1.87082 \dots

Solution steps

2 x^{2} - 7 = 0

Move

7 \cdot

to the right side

2 x^{2} = 7

Divide both sides by

2

x^{2} = \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{2}, x = - \frac{7}{2}

2 r^{2} + 2 r - 5 = 0

4 x^{2} - 19 x = 5

2 ((y + 5) y) = (y + 10) (y + 5)

x, x^{2} + 2 x y - 9 x - 6 y + 18 = 0

x^{2} - 50 \cdot 1 0^{- 6} x + \frac{4}{9} \cdot 1 0^{- 9} = 0

What are the solutions to the equation 2x^2-7*=0 ?
The solutions to the equation 2x^2-7*=0 are x=sqrt(7/2),x=-sqrt(7/2)
Find the zeros of 2x^2-7*=0
The zeros of 2x^2-7*=0 are x=sqrt(7/2),x=-sqrt(7/2)